{"id":1133,"date":"2026-07-05T00:31:06","date_gmt":"2026-07-05T00:31:06","guid":{"rendered":"https:\/\/blog.phantram.online\/phan-tram-diem-trung-binh-hoc-ky\/"},"modified":"2026-07-07T09:35:53","modified_gmt":"2026-07-07T09:35:53","slug":"phan-tram-diem-trung-binh-hoc-ky","status":"publish","type":"post","link":"https:\/\/1phantram.com\/blog\/phan-tram-diem-trung-binh-hoc-ky\/","title":{"rendered":"C\u00e1ch T\u00ednh Ph\u1ea7n Tr\u0103m \u0110i\u1ec3m Trung B\u00ecnh H\u1ecdc K\u1ef3 C\u1ea5p 3"},"content":{"rendered":"

Cu\u1ed1i m\u1ed7i h\u1ecdc k\u1ef3, h\u1ecdc sinh c\u1ea5p 3 l\u1ea1i \u0111\u1ed1i m\u1eb7t v\u1edbi m\u1ed9t c\u00e2u h\u1ecfi quen thu\u1ed9c: “\u0110i\u1ec3m trung b\u00ecnh m\u00f4n c\u1ee7a m\u00ecnh l\u00e0 bao nhi\u00eau, v\u00e0 m\u00ecnh c\u1ea7n bao nhi\u00eau \u0111i\u1ec3m cu\u1ed1i k\u1ef3 \u0111\u1ec3 \u0111\u1ea1t lo\u1ea1i Gi\u1ecfi?”. \u0110\u1eb1ng sau con s\u1ed1 \u0111i\u1ec3m t\u1ed5ng k\u1ebft t\u01b0\u1edfng ch\u1eebng \u0111\u01a1n gi\u1ea3n \u1ea5y l\u00e0 m\u1ed9t lo\u1ea1t ph\u00e9p t\u00ednh li\u00ean quan \u0111\u1ebfn h\u1ec7 s\u1ed1, tr\u1ecdng s\u1ed1 v\u00e0 c\u1ea3 ph\u1ea7n tr\u0103m \u0111i\u1ec3m trung b\u00ecnh<\/strong> c\u1ee7a t\u1eebng c\u1ed9t \u0111i\u1ec3m th\u00e0nh ph\u1ea7n. N\u1ebfu kh\u00f4ng n\u1eafm r\u00f5 c\u00e1ch t\u00ednh, b\u1ea1n r\u1ea5t d\u1ec5 t\u00ednh nh\u1ea7m, \u0111\u1eb7t m\u1ee5c ti\u00eau sai v\u00e0 b\u1ecf l\u1ee1 c\u01a1 h\u1ed9i c\u1ea3i thi\u1ec7n x\u1ebfp lo\u1ea1i h\u1ecdc l\u1ef1c.<\/p>\n

\u0110i\u1ec3m trung b\u00ecnh m\u00f4n h\u1ecdc \u1edf c\u1ea5p 3 Vi\u1ec7t Nam kh\u00f4ng ph\u1ea3i l\u00e0 ph\u00e9p c\u1ed9ng \u0111\u01a1n thu\u1ea7n r\u1ed3i chia cho s\u1ed1 c\u1ed9t \u0111i\u1ec3m. M\u1ed7i lo\u1ea1i \u0111i\u1ec3m \u2014 \u0111i\u1ec3m mi\u1ec7ng, \u0111i\u1ec3m 15 ph\u00fat, \u0111i\u1ec3m 1 ti\u1ebft (ki\u1ec3m tra \u0111\u1ecbnh k\u1ef3) v\u00e0 \u0111i\u1ec3m thi cu\u1ed1i k\u1ef3 \u2014 mang m\u1ed9t h\u1ec7 s\u1ed1 kh\u00e1c nhau. \u0110i\u1ec3m cu\u1ed1i k\u1ef3 th\u01b0\u1eddng c\u00f3 h\u1ec7 s\u1ed1 3, \u0111i\u1ec3m 1 ti\u1ebft h\u1ec7 s\u1ed1 2, c\u00f2n \u0111i\u1ec3m mi\u1ec7ng v\u00e0 15 ph\u00fat h\u1ec7 s\u1ed1 1. Hi\u1ec3u b\u1ea3n ch\u1ea5t c\u1ee7a c\u00e1c h\u1ec7 s\u1ed1 n\u00e0y, v\u00e0 bi\u1ebft m\u1ed7i c\u1ed9t \u0111i\u1ec3m chi\u1ebfm bao nhi\u00eau ph\u1ea7n tr\u0103m \u0111i\u1ec3m trung b\u00ecnh<\/strong> cu\u1ed1i c\u00f9ng, ch\u00ednh l\u00e0 ch\u00eca kh\u00f3a \u0111\u1ec3 b\u1ea1n ki\u1ec3m so\u00e1t k\u1ebft qu\u1ea3 h\u1ecdc t\u1eadp c\u1ee7a m\u00ecnh.<\/p>\n

B\u00e0i vi\u1ebft n\u00e0y h\u01b0\u1edbng d\u1eabn b\u1ea1n t\u1eeb \u0111\u1ea7u \u0111\u1ebfn cu\u1ed1i: c\u00f4ng th\u1ee9c t\u00ednh \u0111i\u1ec3m trung b\u00ecnh m\u00f4n theo h\u1ec7 s\u1ed1, c\u00e1ch quy \u0111\u1ed5i t\u1ef7 tr\u1ecdng t\u1eebng c\u1ed9t \u0111i\u1ec3m sang ph\u1ea7n tr\u0103m, c\u00e1ch t\u00ednh \u0111i\u1ec3m trung b\u00ecnh c\u00e1c m\u00f4n c\u1ea3 h\u1ecdc k\u1ef3, b\u1ea3ng tra c\u1ee9u x\u1ebfp lo\u1ea1i h\u1ecdc l\u1ef1c, h\u00e0ng lo\u1ea1t v\u00ed d\u1ee5 \u0111i\u1ec3m s\u1ed1 th\u1ef1c t\u1ebf c\u1ee7a h\u1ecdc sinh c\u1ea5p 3, nh\u1eefng l\u1ed7i t\u00ednh to\u00e1n ph\u1ed5 bi\u1ebfn v\u00e0 m\u1eb9o t\u1ef1 t\u00ednh nhanh. \u0110\u1ecdc xong, b\u1ea1n s\u1ebd t\u1ef1 tin l\u00e0m ch\u1ee7 m\u1ecdi con s\u1ed1 tr\u00ean h\u1ecdc b\u1ea1.<\/p>\n

\n\ud83d\udc49 T\u00ednh nhanh kh\u00f4ng c\u1ea7n c\u00f4ng th\u1ee9c:<\/strong> N\u1ebfu b\u1ea1n ch\u1ec9 c\u1ea7n bi\u1ebft ngay \u0111i\u1ec3m trung b\u00ecnh m\u00f4n ho\u1eb7c m\u1ed7i c\u1ed9t \u0111i\u1ec3m chi\u1ebfm bao nhi\u00eau ph\u1ea7n tr\u0103m, c\u00f4ng c\u1ee5 t\u1ea1i 1phantram.com<\/strong><\/a> h\u1ed7 tr\u1ee3 t\u00ednh ph\u1ea7n tr\u0103m c\u1ee7a t\u1ed5ng, ph\u1ea7n tr\u0103m tr\u1ecdng s\u1ed1, ph\u1ea7n tr\u0103m t\u0103ng\/gi\u1ea3m \u2014 mi\u1ec5n ph\u00ed, kh\u00f4ng qu\u1ea3ng c\u00e1o, d\u00f9ng m\u01b0\u1ee3t tr\u00ean \u0111i\u1ec7n tho\u1ea1i khi \u0111ang d\u00f2 \u0111i\u1ec3m cu\u1ed1i k\u1ef3.\n<\/div>\n

1. \u0110i\u1ec3m Trung B\u00ecnh M\u00f4n C\u1ea5p 3 L\u00e0 G\u00ec V\u00e0 Vai Tr\u00f2 C\u1ee7a H\u1ec7 S\u1ed1<\/h2>\n

1.1. \u0110\u1ecbnh ngh\u0129a \u0111i\u1ec3m trung b\u00ecnh m\u00f4n<\/h3>\n

\u0110i\u1ec3m trung b\u00ecnh m\u00f4n (\u0110TBm\u00f4n) l\u00e0 con s\u1ed1 ph\u1ea3n \u00e1nh k\u1ebft qu\u1ea3 h\u1ecdc t\u1eadp c\u1ee7a m\u1ed9t m\u00f4n h\u1ecdc trong m\u1ed9t h\u1ecdc k\u1ef3, \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng c\u00e1ch l\u1ea5y t\u1ed5ng c\u00e1c \u0111i\u1ec3m th\u00e0nh ph\u1ea7n \u0111\u00e3 nh\u00e2n h\u1ec7 s\u1ed1, chia cho t\u1ed5ng c\u00e1c h\u1ec7 s\u1ed1. \u0110\u00e2y kh\u00f4ng ph\u1ea3i trung b\u00ecnh c\u1ed9ng \u0111\u01a1n gi\u1ea3n, m\u00e0 l\u00e0 trung b\u00ecnh c\u00f3 tr\u1ecdng s\u1ed1 (weighted average). Ch\u00ednh v\u00ec c\u00f3 tr\u1ecdng s\u1ed1 n\u00ean m\u1ed7i c\u1ed9t \u0111i\u1ec3m \u0111\u00f3ng g\u00f3p m\u1ed9t t\u1ef7 l\u1ec7 ph\u1ea7n tr\u0103m kh\u00e1c nhau v\u00e0o k\u1ebft qu\u1ea3 cu\u1ed1i c\u00f9ng.<\/p>\n

1.2. V\u00ec sao c\u1ea7n h\u1ec7 s\u1ed1 thay v\u00ec trung b\u00ecnh c\u1ed9ng<\/h3>\n

H\u1ec7 s\u1ed1 ph\u1ea3n \u00e1nh m\u1ee9c \u0111\u1ed9 quan tr\u1ecdng v\u00e0 \u0111\u1ed9 kh\u00f3 c\u1ee7a t\u1eebng b\u00e0i ki\u1ec3m tra. M\u1ed9t b\u00e0i thi cu\u1ed1i k\u1ef3 k\u00e9o d\u00e0i 90 ph\u00fat, bao qu\u00e1t to\u00e0n b\u1ed9 ki\u1ebfn th\u1ee9c h\u1ecdc k\u1ef3, r\u00f5 r\u00e0ng ph\u1ea3i “n\u1eb7ng k\u00fd” h\u01a1n m\u1ed9t l\u1ea7n tr\u1ea3 b\u00e0i mi\u1ec7ng 3 ph\u00fat \u0111\u1ea7u gi\u1edd. N\u1ebfu t\u00ednh trung b\u00ecnh c\u1ed9ng, \u0111i\u1ec3m mi\u1ec7ng v\u00e0 \u0111i\u1ec3m cu\u1ed1i k\u1ef3 s\u1ebd c\u00f3 s\u1ee9c n\u1eb7ng ngang nhau \u2014 \u0111i\u1ec1u n\u00e0y kh\u00f4ng c\u00f4ng b\u1eb1ng v\u00e0 kh\u00f4ng ph\u1ea3n \u00e1nh \u0111\u00fang n\u0103ng l\u1ef1c. H\u1ec7 s\u1ed1 gi\u1ea3i quy\u1ebft v\u1ea5n \u0111\u1ec1 n\u00e0y b\u1eb1ng c\u00e1ch nh\u00e2n \u0111i\u1ec3m quan tr\u1ecdng v\u1edbi s\u1ed1 l\u1edbn h\u01a1n.<\/p>\n

1.3. C\u00e1c c\u1ed9t \u0111i\u1ec3m v\u00e0 h\u1ec7 s\u1ed1 theo quy \u0111\u1ecbnh<\/h3>\n

Theo c\u00e1ch t\u00ednh truy\u1ec1n th\u1ed1ng ph\u1ed5 bi\u1ebfn \u1edf c\u1ea5p 3 Vi\u1ec7t Nam, c\u00e1c c\u1ed9t \u0111i\u1ec3m v\u00e0 h\u1ec7 s\u1ed1 nh\u01b0 sau: \u0111i\u1ec3m ki\u1ec3m tra th\u01b0\u1eddng xuy\u00ean (\u0111i\u1ec3m mi\u1ec7ng, 15 ph\u00fat) c\u00f3 h\u1ec7 s\u1ed1 1; \u0111i\u1ec3m ki\u1ec3m tra \u0111\u1ecbnh k\u1ef3 (1 ti\u1ebft) c\u00f3 h\u1ec7 s\u1ed1 2; \u0111i\u1ec3m thi h\u1ecdc k\u1ef3 (cu\u1ed1i k\u1ef3) c\u00f3 h\u1ec7 s\u1ed1 3. Ch\u00ednh b\u1ed9 h\u1ec7 s\u1ed1 n\u00e0y quy\u1ebft \u0111\u1ecbnh ph\u1ea7n tr\u0103m \u0111\u00f3ng g\u00f3p c\u1ee7a m\u1ed7i lo\u1ea1i \u0111i\u1ec3m, v\u00e0 ch\u00fang ta s\u1ebd ph\u00e2n t\u00edch chi ti\u1ebft \u1edf c\u00e1c ph\u1ea7n sau.<\/p>\n

2. C\u00f4ng Th\u1ee9c T\u00ednh \u0110i\u1ec3m Trung B\u00ecnh M\u00f4n Theo H\u1ec7 S\u1ed1<\/h2>\n

2.1. C\u00f4ng th\u1ee9c g\u1ed1c<\/h3>\n

C\u00f4ng th\u1ee9c t\u1ed5ng qu\u00e1t \u0111\u1ec3 t\u00ednh \u0111i\u1ec3m trung b\u00ecnh m\u00f4n m\u1ed9t h\u1ecdc k\u1ef3:<\/p>\n

\n\u0110TBm\u00f4n = (T\u1ed5ng \u0111i\u1ec3m \u00d7 h\u1ec7 s\u1ed1 t\u01b0\u01a1ng \u1ee9ng) \/ (T\u1ed5ng c\u00e1c h\u1ec7 s\u1ed1)<\/strong>\n<\/p>\n

Di\u1ec5n gi\u1ea3i chi ti\u1ebft h\u01a1n v\u1edbi c\u00e1c c\u1ed9t \u0111i\u1ec3m c\u1ea5p 3:<\/p>\n

\n\u0110TBm\u00f4n = (\u0110TX\u00d71 + \u01101ti\u1ebft\u00d72 + \u0110Cu\u1ed1iK\u1ef3\u00d73) \/ (S\u1ed1 h\u1ec7 s\u1ed1)<\/strong>\n<\/p>\n

Trong \u0111\u00f3 \u0110TX l\u00e0 \u0111i\u1ec3m th\u01b0\u1eddng xuy\u00ean (mi\u1ec7ng, 15 ph\u00fat). N\u1ebfu c\u1ea7n \u00f4n l\u1ea1i n\u1ec1n t\u1ea3ng ph\u00e9p t\u00ednh ph\u1ea7n tr\u0103m v\u00e0 tr\u1ecdng s\u1ed1 tr\u01b0\u1edbc khi \u0111i s\u00e2u, xem b\u00e0i c\u00f4ng th\u1ee9c t\u00ednh ph\u1ea7n tr\u0103m<\/a> \u0111\u1ec3 hi\u1ec3u r\u00f5 c\u01a1 ch\u1ebf ph\u1ea7n tr\u0103m v\u00e0 trung b\u00ecnh c\u00f3 tr\u1ecdng s\u1ed1 ho\u1ea1t \u0111\u1ed9ng th\u1ebf n\u00e0o.<\/p>\n

2.2. C\u00e1ch x\u00e1c \u0111\u1ecbnh t\u1ed5ng h\u1ec7 s\u1ed1<\/h3>\n

T\u1ed5ng h\u1ec7 s\u1ed1 b\u1eb1ng t\u1ed5ng s\u1ed1 l\u1ea7n \u0111i\u1ec3m nh\u00e2n v\u1edbi h\u1ec7 s\u1ed1 c\u1ee7a n\u00f3. Gi\u1ea3 s\u1eed m\u1ed9t m\u00f4n c\u00f3 2 \u0111i\u1ec3m mi\u1ec7ng (h\u1ec7 s\u1ed1 1 m\u1ed7i \u0111i\u1ec3m), 1 \u0111i\u1ec3m 15 ph\u00fat (h\u1ec7 s\u1ed1 1), 2 \u0111i\u1ec3m 1 ti\u1ebft (h\u1ec7 s\u1ed1 2 m\u1ed7i \u0111i\u1ec3m), v\u00e0 1 \u0111i\u1ec3m cu\u1ed1i k\u1ef3 (h\u1ec7 s\u1ed1 3). T\u1ed5ng h\u1ec7 s\u1ed1 = (2\u00d71) + (1\u00d71) + (2\u00d72) + (1\u00d73) = 2 + 1 + 4 + 3 = 10. M\u1eabu s\u1ed1 trong c\u00f4ng th\u1ee9c ch\u00ednh l\u00e0 con s\u1ed1 10 n\u00e0y.<\/p>\n

2.3. V\u00ed d\u1ee5 \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c<\/h3>\n

B\u1ea1n Minh h\u1ecdc m\u00f4n To\u00e1n h\u1ecdc k\u1ef3 1 v\u1edbi c\u00e1c \u0111i\u1ec3m: 2 \u0111i\u1ec3m mi\u1ec7ng (8 v\u00e0 7), 1 \u0111i\u1ec3m 15 ph\u00fat (9), 2 \u0111i\u1ec3m 1 ti\u1ebft (7 v\u00e0 8), 1 \u0111i\u1ec3m cu\u1ed1i k\u1ef3 (8).<\/p>\n

T\u1eed s\u1ed1 = (8\u00d71 + 7\u00d71) + (9\u00d71) + (7\u00d72 + 8\u00d72) + (8\u00d73) = 15 + 9 + 30 + 24 = 78<\/p>\n

M\u1eabu s\u1ed1 (t\u1ed5ng h\u1ec7 s\u1ed1) = 2 + 1 + 4 + 3 = 10<\/p>\n

\u0110TBm\u00f4n To\u00e1n = 78 \/ 10 = 7,8<\/strong><\/p>\n

\n\ud83d\udca1 V\u00ed d\u1ee5 minh h\u1ecda b\u1ea3n ch\u1ea5t tr\u1ecdng s\u1ed1:<\/strong> C\u00f9ng b\u1ea1n Minh, n\u1ebfu b\u00e0i cu\u1ed1i k\u1ef3 ch\u1ec9 \u0111\u1ea1t 5 thay v\u00ec 8:
\nT\u1eed s\u1ed1 = 15 + 9 + 30 + (5\u00d73) = 15 + 9 + 30 + 15 = 69
\n\u0110TBm\u00f4n = 69 \/ 10 = 6,9<\/strong>
\nCh\u1ec9 m\u1ed9t c\u1ed9t \u0111i\u1ec3m cu\u1ed1i k\u1ef3 gi\u1ea3m 3 \u0111i\u1ec3m \u0111\u00e3 k\u00e9o trung b\u00ecnh m\u00f4n t\u1ee5t 0,9 \u0111i\u1ec3m \u2014 b\u1eb1ng ch\u1ee9ng cho th\u1ea5y \u0111i\u1ec3m h\u1ec7 s\u1ed1 3 “n\u1eb7ng” th\u1ebf n\u00e0o!\n<\/div>\n

3. Quy \u0110\u1ed5i H\u1ec7 S\u1ed1 Sang Ph\u1ea7n Tr\u0103m \u0110i\u1ec3m Trung B\u00ecnh<\/h2>\n

3.1. V\u00ec sao n\u00ean ngh\u0129 theo ph\u1ea7n tr\u0103m<\/h3>\n

H\u1ec7 s\u1ed1 (1, 2, 3) l\u00e0 ng\u00f4n ng\u1eef c\u1ee7a gi\u00e1o vi\u00ean, nh\u01b0ng ph\u1ea7n tr\u0103m l\u00e0 ng\u00f4n ng\u1eef tr\u1ef1c quan h\u01a1n v\u1edbi h\u1ecdc sinh. Khi bi\u1ebft \u0111i\u1ec3m cu\u1ed1i k\u1ef3 chi\u1ebfm bao nhi\u00eau ph\u1ea7n tr\u0103m \u0111i\u1ec3m trung b\u00ecnh m\u00f4n, b\u1ea1n s\u1ebd bi\u1ebft n\u00ean d\u1ed3n s\u1ee9c v\u00e0o \u0111\u00e2u. Quy \u0111\u1ed5i h\u1ec7 s\u1ed1 sang ph\u1ea7n tr\u0103m gi\u00fap b\u1ea1n “nh\u00ecn th\u1ea5y” s\u1ee9c n\u1eb7ng th\u1ef1c s\u1ef1 c\u1ee7a t\u1eebng c\u1ed9t \u0111i\u1ec3m v\u00e0 l\u1eadp chi\u1ebfn l\u01b0\u1ee3c \u00f4n t\u1eadp th\u00f4ng minh.<\/p>\n

3.2. C\u00e1ch quy \u0111\u1ed5i h\u1ec7 s\u1ed1 th\u00e0nh ph\u1ea7n tr\u0103m<\/h3>\n

Ph\u1ea7n tr\u0103m c\u1ee7a m\u1ed7i c\u1ed9t \u0111i\u1ec3m = (h\u1ec7 s\u1ed1 c\u1ee7a c\u1ed9t \/ t\u1ed5ng h\u1ec7 s\u1ed1) \u00d7 100. V\u1edbi c\u1ea5u tr\u00fac \u0111i\u1ec3m chu\u1ea9n (t\u1ed5ng h\u1ec7 s\u1ed1 = 10 nh\u01b0 v\u00ed d\u1ee5 tr\u00ean), ta c\u00f3 b\u1ea3ng quy \u0111\u1ed5i r\u00f5 r\u00e0ng. C\u00e1ch t\u01b0 duy n\u00e0y gi\u1ed1ng h\u1ec7t vi\u1ec7c ph\u00e2n b\u1ed5 tr\u1ecdng s\u1ed1 trong qu\u1ea3n l\u00fd t\u00e0i ch\u00ednh \u2014 n\u1ebfu b\u1ea1n quan t\u00e2m c\u00e1ch ph\u00e2n b\u1ed5 t\u1ef7 tr\u1ecdng n\u00f3i chung, b\u00e0i qu\u1ea3n l\u00fd t\u00e0i ch\u00ednh c\u00e1 nh\u00e2n<\/a> c\u00f3 nhi\u1ec1u v\u00ed d\u1ee5 v\u1ec1 ph\u00e2n b\u1ed5 theo t\u1ef7 l\u1ec7 ph\u1ea7n tr\u0103m r\u1ea5t h\u1eefu \u00edch.<\/p>\n

3.3. B\u1ea3ng ph\u1ea7n tr\u0103m theo c\u1ea5u tr\u00fac \u0111i\u1ec3m chu\u1ea9n<\/h3>\n

Gi\u1ea3 s\u1eed c\u1ea5u tr\u00fac \u0111i\u1ec3m ph\u1ed5 bi\u1ebfn: 3 \u0111i\u1ec3m th\u01b0\u1eddng xuy\u00ean (h\u1ec7 s\u1ed1 1 m\u1ed7i c\u1ed9t), 2 \u0111i\u1ec3m 1 ti\u1ebft (h\u1ec7 s\u1ed1 2 m\u1ed7i c\u1ed9t), 1 \u0111i\u1ec3m cu\u1ed1i k\u1ef3 (h\u1ec7 s\u1ed1 3). T\u1ed5ng h\u1ec7 s\u1ed1 = 3 + 4 + 3 = 10.<\/p>\n\n\n\n\n\n\n\n\n
Lo\u1ea1i \u0111i\u1ec3m<\/th>\nS\u1ed1 c\u1ed9t<\/th>\nH\u1ec7 s\u1ed1\/c\u1ed9t<\/th>\nT\u1ed5ng h\u1ec7 s\u1ed1<\/th>\n% \u0111i\u1ec3m trung b\u00ecnh<\/th>\n<\/tr>\n<\/thead>\n
\u0110i\u1ec3m th\u01b0\u1eddng xuy\u00ean (mi\u1ec7ng, 15 ph\u00fat)<\/td>\n3<\/td>\n1<\/td>\n3<\/td>\n30%<\/td>\n<\/tr>\n
\u0110i\u1ec3m 1 ti\u1ebft (\u0111\u1ecbnh k\u1ef3)<\/td>\n2<\/td>\n2<\/td>\n4<\/td>\n40%<\/td>\n<\/tr>\n
\u0110i\u1ec3m cu\u1ed1i k\u1ef3<\/td>\n1<\/td>\n3<\/td>\n3<\/td>\n30%<\/td>\n<\/tr>\n
T\u1ed5ng c\u1ed9ng<\/td>\n6<\/td>\n\u2014<\/td>\n10<\/td>\n100%<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Nh\u00ecn b\u1ea3ng n\u00e0y b\u1ea1n th\u1ea5y r\u00f5: nh\u00f3m \u0111i\u1ec3m 1 ti\u1ebft chi\u1ebfm t\u1edbi 40% \u2014 cao nh\u1ea5t trong c\u1ea3 ba nh\u00f3m khi g\u1ed9p l\u1ea1i. Nhi\u1ec1u h\u1ecdc sinh ch\u1ec9 lo b\u00e0i cu\u1ed1i k\u1ef3 m\u00e0 qu\u00ean r\u1eb1ng hai b\u00e0i 1 ti\u1ebft c\u1ed9ng l\u1ea1i c\u00f2n n\u1eb7ng h\u01a1n.<\/p>\n

\n\ud83d\udca1 V\u00ed d\u1ee5 t\u00ednh ph\u1ea7n tr\u0103m m\u1ed9t c\u1ed9t:<\/strong> B\u00e0i thi cu\u1ed1i k\u1ef3 h\u1ec7 s\u1ed1 3, t\u1ed5ng h\u1ec7 s\u1ed1 10.
\n% cu\u1ed1i k\u1ef3 = (3 \/ 10) \u00d7 100 = 30%<\/strong>
\nNgh\u0129a l\u00e0 \u0111i\u1ec3m cu\u1ed1i k\u1ef3 quy\u1ebft \u0111\u1ecbnh 30% \u0111i\u1ec3m trung b\u00ecnh m\u00f4n. N\u1ebfu b\u1ea1n \u0111ang thi\u1ebfu 0,5 \u0111i\u1ec3m \u0111\u1ec3 l\u00ean lo\u1ea1i, c\u1ea3i thi\u1ec7n 30% tr\u1ecdng s\u1ed1 n\u00e0y l\u00e0 con \u0111\u01b0\u1eddng nhanh nh\u1ea5t.\n<\/div>\n

4. V\u00ed D\u1ee5 Th\u1ef1c T\u1ebf T\u00ednh \u0110i\u1ec3m Trung B\u00ecnh Nhi\u1ec1u M\u00f4n<\/h2>\n

4.1. B\u1ea3ng \u0111i\u1ec3m h\u1ecdc k\u1ef3 c\u1ee7a m\u1ed9t h\u1ecdc sinh<\/h3>\n

X\u00e9t b\u1ea1n Lan, h\u1ecdc sinh l\u1edbp 11, c\u00f3 b\u1ea3ng \u0111i\u1ec3m h\u1ecdc k\u1ef3 1 nh\u01b0 sau (m\u1ed7i m\u00f4n \u0111\u00e3 t\u00ednh \u0110TBm\u00f4n theo h\u1ec7 s\u1ed1 c\u1ed9t \u0111i\u1ec3m):<\/p>\n\n\n\n\n\n\n\n\n\n\n
M\u00f4n h\u1ecdc<\/th>\nMi\u1ec7ng\/15p<\/th>\n1 ti\u1ebft<\/th>\nCu\u1ed1i k\u1ef3<\/th>\n\u0110TBm\u00f4n<\/th>\n<\/tr>\n<\/thead>\n
To\u00e1n<\/td>\n8; 9<\/td>\n7; 8<\/td>\n8<\/td>\n7,9<\/td>\n<\/tr>\n
Ng\u1eef v\u0103n<\/td>\n7; 8<\/td>\n7; 7<\/td>\n7<\/td>\n7,1<\/td>\n<\/tr>\n
Ti\u1ebfng Anh<\/td>\n9; 8<\/td>\n8; 9<\/td>\n9<\/td>\n8,7<\/td>\n<\/tr>\n
V\u1eadt l\u00fd<\/td>\n6; 7<\/td>\n6; 7<\/td>\n7<\/td>\n6,7<\/td>\n<\/tr>\n
H\u00f3a h\u1ecdc<\/td>\n7; 8<\/td>\n8; 7<\/td>\n8<\/td>\n7,7<\/td>\n<\/tr>\n
Sinh h\u1ecdc<\/td>\n8; 8<\/td>\n7; 8<\/td>\n8<\/td>\n7,8<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

4.2. C\u00f4ng th\u1ee9c t\u00ednh \u0111i\u1ec3m trung b\u00ecnh t\u1ea5t c\u1ea3 c\u00e1c m\u00f4n<\/h3>\n

\u0110i\u1ec3m trung b\u00ecnh c\u00e1c m\u00f4n h\u1ecdc k\u1ef3 (\u0110TBhk) l\u00e0 trung b\u00ecnh c\u1ed9ng \u0111\u01a1n gi\u1ea3n c\u1ee7a c\u00e1c \u0110TBm\u00f4n (khi t\u1ea5t c\u1ea3 m\u00f4n t\u00ednh h\u1ec7 s\u1ed1 1 nh\u01b0 nhau), ho\u1eb7c c\u00f3 th\u1ec3 c\u00f3 h\u1ec7 s\u1ed1 m\u00f4n t\u00f9y quy \u0111\u1ecbnh. C\u00f4ng th\u1ee9c c\u01a1 b\u1ea3n:<\/p>\n

\n\u0110TBhk = (T\u1ed5ng \u0110TBm\u00f4n \u00d7 h\u1ec7 s\u1ed1 m\u00f4n) \/ (T\u1ed5ng h\u1ec7 s\u1ed1 m\u00f4n)<\/strong>\n<\/p>\n

4.3. T\u00ednh \u0110TBhk cho b\u1ea1n Lan<\/h3>\n

Gi\u1ea3 s\u1eed t\u1ea5t c\u1ea3 c\u00e1c m\u00f4n tr\u00ean c\u00f3 h\u1ec7 s\u1ed1 m\u00f4n = 1 (tr\u01b0\u1eddng h\u1ee3p \u0111\u01a1n gi\u1ea3n, ch\u1ec9 6 m\u00f4n \u0111\u1ec3 minh h\u1ecda):<\/p>\n

T\u1ed5ng \u0110TBm\u00f4n = 7,9 + 7,1 + 8,7 + 6,7 + 7,7 + 7,8 = 45,9<\/p>\n

\u0110TBhk = 45,9 \/ 6 = 7,65 \u2248 7,7<\/strong><\/p>\n

V\u1edbi \u0110TBhk 7,65 v\u00e0 kh\u00f4ng c\u00f3 m\u00f4n n\u00e0o d\u01b0\u1edbi 5, b\u1ea1n Lan \u0111\u1ee7 \u0111i\u1ec1u ki\u1ec7n x\u1ebfp lo\u1ea1i h\u1ecdc l\u1ef1c Kh\u00e1 (chi ti\u1ebft ng\u01b0\u1ee1ng \u1edf ph\u1ea7n sau).<\/p>\n

\n\ud83d\udca1 V\u00ed d\u1ee5 h\u1ec7 s\u1ed1 m\u00f4n kh\u00e1c nhau:<\/strong> \u1ede m\u1ed9t s\u1ed1 c\u00e1ch t\u00ednh, m\u00f4n To\u00e1n v\u00e0 V\u0103n c\u00f3 h\u1ec7 s\u1ed1 2, c\u00e1c m\u00f4n c\u00f2n l\u1ea1i h\u1ec7 s\u1ed1 1. Khi \u0111\u00f3 m\u00f4n To\u00e1n\/V\u0103n “n\u1eb7ng” g\u1ea5p \u0111\u00f4i. N\u1ebfu To\u00e1n c\u1ee7a Lan l\u00e0 7,9 (h\u1ec7 s\u1ed1 2) th\u00ec n\u00f3 \u0111\u00f3ng g\u00f3p 15,8 v\u00e0o t\u1eed s\u1ed1 thay v\u00ec 7,9 \u2014 thay \u0111\u1ed5i \u0111\u00e1ng k\u1ec3 \u0110TBhk. Lu\u00f4n ki\u1ec3m tra quy \u0111\u1ecbnh h\u1ec7 s\u1ed1 m\u00f4n c\u1ee7a tr\u01b0\u1eddng b\u1ea1n.\n<\/div>\n

5. B\u1ea3ng X\u1ebfp Lo\u1ea1i H\u1ecdc L\u1ef1c Theo \u0110i\u1ec3m Trung B\u00ecnh<\/h2>\n

5.1. C\u00e1c ng\u01b0\u1ee1ng x\u1ebfp lo\u1ea1i<\/h3>\n

X\u1ebfp lo\u1ea1i h\u1ecdc l\u1ef1c c\u1ea5p 3 d\u1ef1a tr\u00ean \u0110TBhk k\u1ebft h\u1ee3p v\u1edbi \u0111i\u1ec1u ki\u1ec7n v\u1ec1 \u0111i\u1ec3m s\u00e0n t\u1eebng m\u00f4n. B\u1ea3ng tra c\u1ee9u ng\u01b0\u1ee1ng ph\u1ed5 bi\u1ebfn:<\/p>\n\n\n\n\n\n\n\n\n\n
X\u1ebfp lo\u1ea1i<\/th>\n\u0110TBhk<\/th>\n\u0110i\u1ec1u ki\u1ec7n k\u00e8m theo<\/th>\n<\/tr>\n<\/thead>\n
Gi\u1ecfi<\/td>\n\u2265 8,0<\/td>\nKh\u00f4ng m\u00f4n n\u00e0o d\u01b0\u1edbi 6,5; m\u00f4n To\u00e1n ho\u1eb7c V\u0103n \u2265 8,0<\/td>\n<\/tr>\n
Kh\u00e1<\/td>\n6,5 \u2013 7,9<\/td>\nKh\u00f4ng m\u00f4n n\u00e0o d\u01b0\u1edbi 5,0; m\u00f4n To\u00e1n ho\u1eb7c V\u0103n \u2265 6,5<\/td>\n<\/tr>\n
Trung b\u00ecnh<\/td>\n5,0 \u2013 6,4<\/td>\nKh\u00f4ng m\u00f4n n\u00e0o d\u01b0\u1edbi 3,5; To\u00e1n ho\u1eb7c V\u0103n \u2265 5,0<\/td>\n<\/tr>\n
Y\u1ebfu<\/td>\n3,5 \u2013 4,9<\/td>\nKh\u00f4ng m\u00f4n n\u00e0o d\u01b0\u1edbi 2,0<\/td>\n<\/tr>\n
K\u00e9m<\/td>\n< 3,5<\/td>\n\u2014<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

5.2. V\u00ec sao c\u1ea7n c\u1ea3 \u0111i\u1ec3m s\u00e0n t\u1eebng m\u00f4n<\/h3>\n

X\u1ebfp lo\u1ea1i kh\u00f4ng ch\u1ec9 nh\u00ecn \u0110TBhk. M\u1ed9t h\u1ecdc sinh c\u00f3 \u0110TBhk 8,2 nh\u01b0ng c\u00f3 m\u1ed9t m\u00f4n b\u1ecb 5,0 s\u1ebd kh\u00f4ng \u0111\u01b0\u1ee3c x\u1ebfp Gi\u1ecfi (v\u00ec \u0111i\u1ec1u ki\u1ec7n Gi\u1ecfi y\u00eau c\u1ea7u kh\u00f4ng m\u00f4n n\u00e0o d\u01b0\u1edbi 6,5). \u0110\u00e2y l\u00e0 l\u00fd do b\u1ea1n kh\u00f4ng th\u1ec3 “g\u00e1nh” \u0111i\u1ec3m trung b\u00ecnh b\u1eb1ng v\u00e0i m\u00f4n c\u1ef1c cao r\u1ed3i b\u1ecf b\u00ea m\u00f4n kh\u00e1c \u2014 c\u01a1 ch\u1ebf \u0111i\u1ec3m s\u00e0n bu\u1ed9c b\u1ea1n h\u1ecdc \u0111\u1ec1u.<\/p>\n

5.3. T\u00ednh ph\u1ea7n tr\u0103m kho\u1ea3ng c\u00e1ch t\u1edbi lo\u1ea1i cao h\u01a1n<\/h3>\n

Gi\u1ea3 s\u1eed b\u1ea1n \u0111ang c\u00f3 \u0110TBhk 7,5 v\u00e0 mu\u1ed1n l\u00ean Gi\u1ecfi (c\u1ea7n 8,0). Kho\u1ea3ng c\u00e1ch l\u00e0 0,5 \u0111i\u1ec3m. X\u00e9t theo ph\u1ea7n tr\u0103m: 0,5 \/ 8,0 \u00d7 100 = 6,25% \u2014 b\u1ea1n c\u1ea7n c\u1ea3i thi\u1ec7n kho\u1ea3ng 6,25% so v\u1edbi ng\u01b0\u1ee1ng Gi\u1ecfi. C\u00e1ch t\u01b0 duy ph\u1ea7n tr\u0103m ch\u00eanh l\u1ec7ch n\u00e0y gi\u1ed1ng vi\u1ec7c t\u00ednh t\u0103ng tr\u01b0\u1edfng, t\u01b0\u01a1ng t\u1ef1 kh\u00e1i ni\u1ec7m trong b\u00e0i CAGR l\u00e0 g\u00ec<\/a> khi \u0111o t\u1ed1c \u0111\u1ed9 t\u0103ng qua c\u00e1c m\u1ed1c.<\/p>\n

6. C\u00e1ch T\u00ednh \u0110i\u1ec3m Cu\u1ed1i K\u1ef3 C\u1ea7n \u0110\u1ea1t \u0110\u1ec3 L\u00ean Lo\u1ea1i<\/h2>\n

6.1. B\u00e0i to\u00e1n ng\u01b0\u1ee3c: t\u00ecm \u0111i\u1ec3m c\u1ea7n thi\u1ebft<\/h3>\n

\u0110\u00e2y l\u00e0 d\u1ea1ng b\u00e0i h\u1ecdc sinh quan t\u00e2m nh\u1ea5t tr\u01b0\u1edbc k\u1ef3 thi: “M\u00ecnh c\u1ea7n bao nhi\u00eau \u0111i\u1ec3m cu\u1ed1i k\u1ef3 \u0111\u1ec3 \u0111\u1ea1t \u0110TBm\u00f4n mong mu\u1ed1n?”. Ta d\u00f9ng c\u00f4ng th\u1ee9c ng\u01b0\u1ee3c t\u1eeb c\u00f4ng th\u1ee9c trung b\u00ecnh c\u00f3 tr\u1ecdng s\u1ed1. G\u1ecdi X l\u00e0 \u0111i\u1ec3m cu\u1ed1i k\u1ef3 c\u1ea7n t\u00ecm.<\/p>\n

\nX = (\u0110TBm\u1ee5c ti\u00eau \u00d7 T\u1ed5ng h\u1ec7 s\u1ed1 \u2212 T\u1ed5ng \u0111i\u1ec3m kh\u00e1c \u0111\u00e3 nh\u00e2n h\u1ec7 s\u1ed1) \/ H\u1ec7 s\u1ed1 cu\u1ed1i k\u1ef3<\/strong>\n<\/p>\n

6.2. V\u00ed d\u1ee5 t\u00ednh \u0111i\u1ec3m cu\u1ed1i k\u1ef3 c\u1ea7n \u0111\u1ea1t<\/h3>\n

B\u1ea1n Nam h\u1ecdc m\u00f4n H\u00f3a, \u0111\u00e3 c\u00f3: 2 \u0111i\u1ec3m mi\u1ec7ng\/15p (7 v\u00e0 8, h\u1ec7 s\u1ed1 1), 2 \u0111i\u1ec3m 1 ti\u1ebft (7 v\u00e0 6, h\u1ec7 s\u1ed1 2). T\u1ed5ng h\u1ec7 s\u1ed1 c\u00e1c c\u1ed9t \u0111\u00e3 c\u00f3 = 2 + 4 = 6. \u0110i\u1ec3m cu\u1ed1i k\u1ef3 h\u1ec7 s\u1ed1 3, t\u1ed5ng h\u1ec7 s\u1ed1 to\u00e0n m\u00f4n = 6 + 3 = 9. Nam mu\u1ed1n \u0110TBm\u00f4n = 7,0.<\/p>\n

T\u1ed5ng \u0111i\u1ec3m \u0111\u00e3 c\u00f3 (\u0111\u00e3 nh\u00e2n h\u1ec7 s\u1ed1) = (7\u00d71 + 8\u00d71) + (7\u00d72 + 6\u00d72) = 15 + 26 = 41<\/p>\n

X = (7,0 \u00d7 9 \u2212 41) \/ 3 = (63 \u2212 41) \/ 3 = 22 \/ 3 = 7,33<\/strong><\/p>\n

V\u1eady Nam c\u1ea7n \u0111\u1ea1t \u00edt nh\u1ea5t 7,33 (l\u00e0m tr\u00f2n l\u00ean 7,5) \u1edf b\u00e0i cu\u1ed1i k\u1ef3 \u0111\u1ec3 \u0110TBm\u00f4n H\u00f3a \u0111\u1ea1t 7,0.<\/p>\n

6.3. B\u1ea3ng tra nhanh \u0111i\u1ec3m cu\u1ed1i k\u1ef3 c\u1ea7n \u0111\u1ea1t<\/h3>\n

V\u1edbi m\u00f4n c\u00f3 t\u1ed5ng \u0111i\u1ec3m c\u00e1c c\u1ed9t kh\u00e1c (\u0111\u00e3 nh\u00e2n h\u1ec7 s\u1ed1) = 41, h\u1ec7 s\u1ed1 cu\u1ed1i k\u1ef3 3, t\u1ed5ng h\u1ec7 s\u1ed1 9, b\u1ea3ng tra \u0111i\u1ec3m X c\u1ea7n \u0111\u1ea1t cho t\u1eebng m\u1ee5c ti\u00eau:<\/p>\n\n\n\n\n\n\n\n\n
\u0110TBm\u00f4n m\u1ee5c ti\u00eau<\/th>\nPh\u00e9p t\u00ednh X<\/th>\n\u0110i\u1ec3m cu\u1ed1i k\u1ef3 c\u1ea7n \u0111\u1ea1t<\/th>\n<\/tr>\n<\/thead>\n
6,5<\/td>\n(6,5\u00d79 \u2212 41)\/3<\/td>\n5,83<\/td>\n<\/tr>\n
7,0<\/td>\n(7,0\u00d79 \u2212 41)\/3<\/td>\n7,33<\/td>\n<\/tr>\n
7,5<\/td>\n(7,5\u00d79 \u2212 41)\/3<\/td>\n8,83<\/td>\n<\/tr>\n
8,0<\/td>\n(8,0\u00d79 \u2212 41)\/3<\/td>\n10,33 (b\u1ea5t kh\u1ea3 thi)<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
\n\ud83d\udca1 B\u00e0i h\u1ecdc t\u1eeb b\u1ea3ng tra:<\/strong> \u0110\u1ec3 \u0111\u1ea1t \u0110TBm\u00f4n 8,0, Nam c\u1ea7n 10,33 \u0111i\u1ec3m cu\u1ed1i k\u1ef3 \u2014 v\u01b0\u1ee3t qu\u00e1 thang 10, t\u1ee9c l\u00e0 kh\u00f4ng th\u1ec3<\/strong>. \u0110i\u1ec1u n\u00e0y cho th\u1ea5y n\u1ebfu \u0111i\u1ec3m c\u00e1c c\u1ed9t \u0111\u1ea7u (mi\u1ec7ng, 1 ti\u1ebft) qu\u00e1 th\u1ea5p, d\u00f9 b\u00e0i cu\u1ed1i k\u1ef3 \u0111\u1ea1t \u0111i\u1ec3m t\u1ed1i \u0111a c\u0169ng kh\u00f4ng c\u1ee9u \u0111\u01b0\u1ee3c. B\u00e0i h\u1ecdc: \u0111\u1eebng coi th\u01b0\u1eddng c\u00e1c c\u1ed9t \u0111i\u1ec3m h\u1ec7 s\u1ed1 1 v\u00e0 2!\n<\/div>\n

7. Nh\u1eefng L\u1ed7i Th\u01b0\u1eddng G\u1eb7p Khi T\u00ednh Ph\u1ea7n Tr\u0103m \u0110i\u1ec3m Trung B\u00ecnh<\/h2>\n

7.1. Nh\u1ea7m trung b\u00ecnh c\u1ed9ng v\u1edbi trung b\u00ecnh c\u00f3 tr\u1ecdng s\u1ed1<\/h3>\n

L\u1ed7i ph\u1ed5 bi\u1ebfn nh\u1ea5t: c\u1ed9ng t\u1ea5t c\u1ea3 \u0111i\u1ec3m r\u1ed3i chia cho s\u1ed1 c\u1ed9t m\u00e0 qu\u00ean nh\u00e2n h\u1ec7 s\u1ed1. V\u00ed d\u1ee5 \u0111i\u1ec3m 8, 7, 9, 7, 8, 8 \u2014 n\u1ebfu c\u1ed9ng chia 6 s\u1ebd ra 7,83, nh\u01b0ng n\u1ebfu t\u00ednh \u0111\u00fang theo h\u1ec7 s\u1ed1 (\u0111i\u1ec3m cu\u1ed1i c\u00f9ng h\u1ec7 s\u1ed1 3) k\u1ebft qu\u1ea3 s\u1ebd kh\u00e1c. Lu\u00f4n nh\u1edb: \u0111i\u1ec3m 1 ti\u1ebft v\u00e0 cu\u1ed1i k\u1ef3 ph\u1ea3i nh\u00e2n h\u1ec7 s\u1ed1 tr\u01b0\u1edbc khi c\u1ed9ng.<\/p>\n

7.2. Qu\u00ean \u0111i\u1ec3m s\u00e0n t\u1eebng m\u00f4n khi x\u1ebfp lo\u1ea1i<\/h3>\n

Nhi\u1ec1u h\u1ecdc sinh t\u00ednh \u0111\u00fang \u0110TBhk 8,1 r\u1ed3i t\u1ef1 tin m\u00ecnh \u0111\u1ea1t Gi\u1ecfi, nh\u01b0ng qu\u00ean r\u1eb1ng c\u00f3 m\u1ed9t m\u00f4n b\u1ecb 6,0 (d\u01b0\u1edbi ng\u01b0\u1ee1ng 6,5 c\u1ee7a lo\u1ea1i Gi\u1ecfi) n\u00ean b\u1ecb t\u1ee5t xu\u1ed1ng Kh\u00e1. Lu\u00f4n ki\u1ec3m tra \u0111i\u1ec3m s\u00e0n t\u1eebng m\u00f4n song song v\u1edbi \u0110TBhk.<\/p>\n

7.3. Sai s\u00f3t khi l\u00e0m tr\u00f2n<\/h3>\n

\u0110TBm\u00f4n th\u01b0\u1eddng \u0111\u01b0\u1ee3c l\u00e0m tr\u00f2n \u0111\u1ebfn 1 ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n, c\u00f2n \u0110TBhk c\u0169ng v\u1eady. L\u00e0m tr\u00f2n qu\u00e1 s\u1edbm \u1edf b\u01b0\u1edbc trung gian c\u00f3 th\u1ec3 g\u00e2y sai l\u1ec7ch. V\u00ed d\u1ee5 n\u1ebfu b\u1ea1n l\u00e0m tr\u00f2n 7,65 th\u00e0nh 7,7 r\u1ed3i m\u1edbi c\u1ed9ng v\u1edbi c\u00e1c m\u00f4n kh\u00e1c, k\u1ebft qu\u1ea3 cu\u1ed1i c\u00f3 th\u1ec3 l\u1ec7ch so v\u1edbi l\u00e0m tr\u00f2n \u1edf b\u01b0\u1edbc cu\u1ed1i. Nguy\u00ean t\u1eafc: ch\u1ec9 l\u00e0m tr\u00f2n \u1edf k\u1ebft qu\u1ea3 cu\u1ed1i c\u00f9ng.<\/p>\n

\n\ud83d\udca1 V\u00ed d\u1ee5 l\u1ed7i l\u00e0m tr\u00f2n:<\/strong> Ba m\u00f4n c\u00f3 \u0110TBm\u00f4n th\u1ef1c 7,65; 8,45; 6,85.
\nL\u00e0m tr\u00f2n s\u1edbm: 7,7 + 8,5 + 6,9 = 23,1 \u2192 \/3 = 7,70
\nL\u00e0m tr\u00f2n cu\u1ed1i: (7,65 + 8,45 + 6,85)\/3 = 22,95\/3 = 7,65
\nCh\u00eanh 0,05 \u2014 nh\u1ecf nh\u01b0ng \u0111\u1ee7 \u0111\u1ea9y b\u1ea1n qua\/kh\u00f4ng qua m\u1ed9t ng\u01b0\u1ee1ng x\u1ebfp lo\u1ea1i s\u00e1t n\u00fat!\n<\/div>\n

7.4. Nh\u1ea7m l\u1eabn gi\u1eefa t\u0103ng \u0111i\u1ec3m tuy\u1ec7t \u0111\u1ed1i v\u00e0 ph\u1ea7n tr\u0103m<\/h3>\n

Khi \u0111i\u1ec3m cu\u1ed1i k\u1ef3 t\u0103ng t\u1eeb 6 l\u00ean 8, \u0111\u00f3 l\u00e0 t\u0103ng 2 \u0111i\u1ec3m tuy\u1ec7t \u0111\u1ed1i, nh\u01b0ng v\u1ec1 ph\u1ea7n tr\u0103m l\u00e0 t\u0103ng (8\u22126)\/6 \u00d7 100 = 33,3%. Hi\u1ec3u r\u00f5 kh\u00e1i ni\u1ec7m n\u00e0y r\u1ea5t quan tr\u1ecdng khi b\u1ea1n so s\u00e1nh ti\u1ebfn b\u1ed9 gi\u1eefa c\u00e1c k\u1ef3. \u0110\u1ec3 n\u1eafm ch\u1eafc c\u00e1ch t\u00ednh t\u0103ng\/gi\u1ea3m theo ph\u1ea7n tr\u0103m, xem th\u00eam b\u00e0i ROI l\u00e0 g\u00ec v\u00e0 c\u00e1ch t\u00ednh<\/a> \u2014 c\u00f9ng nguy\u00ean l\u00fd so s\u00e1nh gi\u00e1 tr\u1ecb m\u1edbi v\u1edbi gi\u00e1 tr\u1ecb g\u1ed1c.<\/p>\n

8. M\u1eb9o T\u1ef1 T\u00ednh Nhanh V\u00e0 Qu\u1ea3n L\u00fd \u0110i\u1ec3m S\u1ed1 C\u1ea3 N\u0103m<\/h2>\n

8.1. L\u1eadp b\u1ea3ng theo d\u00f5i \u0111i\u1ec3m ngay t\u1eeb \u0111\u1ea7u k\u1ef3<\/h3>\n

\u0110\u1eebng \u0111\u1ee3i \u0111\u1ebfn cu\u1ed1i k\u1ef3 m\u1edbi t\u00ednh. H\u00e3y l\u1eadp m\u1ed9t b\u1ea3ng ghi \u0111i\u1ec3m ngay t\u1eeb tu\u1ea7n \u0111\u1ea7u, c\u1eadp nh\u1eadt m\u1ed7i khi c\u00f3 \u0111i\u1ec3m m\u1edbi. B\u1ea3ng n\u00e0y gi\u00fap b\u1ea1n lu\u00f4n bi\u1ebft \u0110TBm\u00f4n hi\u1ec7n t\u1ea1i v\u00e0 c\u1ea7n bao nhi\u00eau \u0111i\u1ec3m cu\u1ed1i k\u1ef3 \u0111\u1ec3 \u0111\u1ea1t m\u1ee5c ti\u00eau. Ki\u1ec3m so\u00e1t s\u1edbm gi\u00fap b\u1ea1n \u0111i\u1ec1u ch\u1ec9nh vi\u1ec7c h\u1ecdc k\u1ecbp th\u1eddi thay v\u00ec “n\u01b0\u1edbc \u0111\u1ebfn ch\u00e2n m\u1edbi nh\u1ea3y”.<\/p>\n

8.2. \u01afu ti\u00ean c\u1ed9t \u0111i\u1ec3m h\u1ec7 s\u1ed1 cao<\/h3>\n

V\u00ec \u0111i\u1ec3m 1 ti\u1ebft (h\u1ec7 s\u1ed1 2) v\u00e0 cu\u1ed1i k\u1ef3 (h\u1ec7 s\u1ed1 3) chi\u1ebfm ph\u1ea7n tr\u0103m l\u1edbn, h\u00e3y d\u1ed3n n\u0103ng l\u01b0\u1ee3ng \u00f4n t\u1eadp k\u1ef9 nh\u1ea5t cho hai lo\u1ea1i n\u00e0y. M\u1ed9t \u0111i\u1ec3m 10 mi\u1ec7ng ch\u1ec9 \u0111\u00f3ng g\u00f3p 10% (n\u1ebfu t\u1ed5ng h\u1ec7 s\u1ed1 10), trong khi m\u1ed9t \u0111i\u1ec3m 10 cu\u1ed1i k\u1ef3 \u0111\u00f3ng g\u00f3p 30%. C\u00f9ng c\u00f4ng s\u1ee9c, h\u00e3y \u0111\u1ea7u t\u01b0 v\u00e0o n\u01a1i cho “l\u1ee3i su\u1ea5t” cao nh\u1ea5t.<\/p>\n

8.3. \u00c1p d\u1ee5ng t\u01b0 duy l\u00e3i k\u00e9p cho vi\u1ec7c h\u1ecdc<\/h3>\n

\u0110i\u1ec3m s\u1ed1 c\u1ea3i thi\u1ec7n \u0111\u1ec1u \u0111\u1eb7n qua t\u1eebng k\u1ef3 c\u00f3 hi\u1ec7u \u1ee9ng t\u00edch l\u0169y gi\u1ed1ng l\u00e3i k\u00e9p: n\u1ec1n t\u1ea3ng v\u1eefng \u1edf k\u1ef3 1 gi\u00fap b\u1ea1n h\u1ecdc nh\u1eb9 nh\u00e0ng h\u01a1n \u1edf k\u1ef3 2, k\u00e9o \u0111i\u1ec3m c\u1ea3 n\u0103m l\u00ean. N\u1ebfu b\u1ea1n t\u00f2 m\u00f2 v\u1ec1 s\u1ee9c m\u1ea1nh c\u1ee7a t\u00edch l\u0169y theo th\u1eddi gian, b\u00e0i l\u00e3i k\u00e9p l\u00e0 g\u00ec<\/a> gi\u1ea3i th\u00edch r\u1ea5t hay nguy\u00ean l\u00fd “t\u00edch ti\u1ec3u th\u00e0nh \u0111\u1ea1i” c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng cho c\u1ea3 ti\u1ec1n b\u1ea1c l\u1eabn ki\u1ebfn th\u1ee9c.<\/p>\n

8.4. D\u00f9ng c\u00f4ng c\u1ee5 t\u00ednh online \u0111\u1ec3 tr\u00e1nh sai s\u00f3t<\/h3>\n

V\u1edbi nh\u1eefng ph\u00e9p t\u00ednh nhi\u1ec1u c\u1ed9t \u0111i\u1ec3m v\u00e0 h\u1ec7 s\u1ed1, t\u00ednh tay d\u1ec5 nh\u1ea7m. D\u00f9ng c\u00f4ng c\u1ee5 t\u00ednh ph\u1ea7n tr\u0103m v\u00e0 tr\u1ecdng s\u1ed1 online gi\u00fap b\u1ea1n c\u00f3 k\u1ebft qu\u1ea3 ch\u00ednh x\u00e1c trong v\u00e0i gi\u00e2y, \u0111\u1eb7c bi\u1ec7t khi c\u1ea7n th\u1eed nhi\u1ec1u k\u1ecbch b\u1ea3n “n\u1ebfu cu\u1ed1i k\u1ef3 \u0111\u01b0\u1ee3c X th\u00ec \u0110TB l\u00e0 bao nhi\u00eau”. Kh\u00e1i ni\u1ec7m \u0111i\u1ec3m trung b\u00ecnh c\u00f3 tr\u1ecdng s\u1ed1 c\u0169ng ch\u00ednh l\u00e0 c\u00e1ch c\u00e1c h\u1ec7 th\u1ed1ng GPA qu\u1ed1c t\u1ebf ho\u1ea1t \u0111\u1ed9ng \u2014 b\u1ea1n c\u00f3 th\u1ec3 \u0111\u1ecdc th\u00eam v\u1ec1 \u0111i\u1ec3m trung b\u00ecnh (GPA) tr\u00ean Wikipedia<\/a> \u0111\u1ec3 hi\u1ec3u b\u1ee9c tranh r\u1ed9ng h\u01a1n.<\/p>\n

9. C\u00e2u H\u1ecfi Th\u01b0\u1eddng G\u1eb7p (FAQ)<\/h2>\n

9.1. \u0110i\u1ec3m mi\u1ec7ng c\u00f3 h\u1ec7 s\u1ed1 bao nhi\u00eau?<\/h3>\n

\u0110i\u1ec3m mi\u1ec7ng thu\u1ed9c nh\u00f3m \u0111i\u1ec3m ki\u1ec3m tra th\u01b0\u1eddng xuy\u00ean, c\u00f3 h\u1ec7 s\u1ed1 1 \u2014 th\u1ea5p nh\u1ea5t trong c\u00e1c lo\u1ea1i \u0111i\u1ec3m. C\u00f9ng nh\u00f3m v\u1edbi \u0111i\u1ec3m 15 ph\u00fat. D\u00f9 h\u1ec7 s\u1ed1 th\u1ea5p, \u0111i\u1ec3m mi\u1ec7ng v\u1eabn g\u00f3p ph\u1ea7n v\u00e0o \u0110TBm\u00f4n n\u00ean \u0111\u1eebng b\u1ecf qua.<\/p>\n

9.2. \u0110i\u1ec3m cu\u1ed1i k\u1ef3 chi\u1ebfm bao nhi\u00eau ph\u1ea7n tr\u0103m \u0111i\u1ec3m trung b\u00ecnh m\u00f4n?<\/h3>\n

T\u00f9y t\u1ed5ng h\u1ec7 s\u1ed1. N\u1ebfu t\u1ed5ng h\u1ec7 s\u1ed1 l\u00e0 10 v\u00e0 cu\u1ed1i k\u1ef3 h\u1ec7 s\u1ed1 3 th\u00ec cu\u1ed1i k\u1ef3 chi\u1ebfm 30%. N\u1ebfu m\u00f4n c\u00f3 \u00edt c\u1ed9t \u0111i\u1ec3m h\u01a1n (v\u00ed d\u1ee5 t\u1ed5ng h\u1ec7 s\u1ed1 6, cu\u1ed1i k\u1ef3 h\u1ec7 s\u1ed1 3) th\u00ec cu\u1ed1i k\u1ef3 chi\u1ebfm t\u1edbi 50%. Lu\u00f4n t\u00ednh theo c\u1ea5u tr\u00fac c\u1ed9t \u0111i\u1ec3m c\u1ee5 th\u1ec3 c\u1ee7a m\u00f4n \u0111\u00f3.<\/p>\n

9.3. L\u00e0m sao t\u00ednh \u0111i\u1ec3m cu\u1ed1i k\u1ef3 c\u1ea7n \u0111\u1ea1t \u0111\u1ec3 l\u00ean lo\u1ea1i Gi\u1ecfi?<\/h3>\n

D\u00f9ng c\u00f4ng th\u1ee9c ng\u01b0\u1ee3c: X = (\u0110TBm\u1ee5c ti\u00eau \u00d7 t\u1ed5ng h\u1ec7 s\u1ed1 \u2212 t\u1ed5ng \u0111i\u1ec3m kh\u00e1c \u0111\u00e3 nh\u00e2n h\u1ec7 s\u1ed1) \/ h\u1ec7 s\u1ed1 cu\u1ed1i k\u1ef3. N\u1ebfu k\u1ebft qu\u1ea3 X v\u01b0\u1ee3t qu\u00e1 10 th\u00ec m\u1ee5c ti\u00eau \u0111\u00f3 b\u1ea5t kh\u1ea3 thi v\u1edbi m\u00f4n n\u00e0y \u2014 c\u1ea7n c\u1ea3i thi\u1ec7n t\u1eeb c\u00e1c c\u1ed9t \u0111i\u1ec3m kh\u00e1c ho\u1eb7c ch\u1ecdn m\u1ee5c ti\u00eau th\u1ea5p h\u01a1n.<\/p>\n

9.4. \u0110TBhk \u0111\u01b0\u1ee3c l\u00e0m tr\u00f2n th\u1ebf n\u00e0o?<\/h3>\n

\u0110i\u1ec3m trung b\u00ecnh h\u1ecdc k\u1ef3 th\u01b0\u1eddng \u0111\u01b0\u1ee3c l\u00e0m tr\u00f2n \u0111\u1ebfn 1 ch\u1eef s\u1ed1 th\u1eadp ph\u00e2n theo quy t\u1eafc l\u00e0m tr\u00f2n th\u00f4ng th\u01b0\u1eddng (0,05 tr\u1edf l\u00ean l\u00e0m tr\u00f2n l\u00ean). Ch\u1ec9 l\u00e0m tr\u00f2n \u1edf k\u1ebft qu\u1ea3 cu\u1ed1i c\u00f9ng, kh\u00f4ng l\u00e0m tr\u00f2n \u1edf c\u00e1c b\u01b0\u1edbc trung gian \u0111\u1ec3 tr\u00e1nh sai l\u1ec7ch t\u00edch l\u0169y.<\/p>\n

9.5. C\u00f3 ph\u1ea3i c\u1ee9 \u0110TBhk \u2265 8,0 l\u00e0 x\u1ebfp lo\u1ea1i Gi\u1ecfi?<\/h3>\n

Kh\u00f4ng. Ngo\u00e0i \u0110TBhk \u2265 8,0, c\u00f2n c\u1ea7n \u0111i\u1ec1u ki\u1ec7n kh\u00f4ng m\u00f4n n\u00e0o d\u01b0\u1edbi 6,5 v\u00e0 m\u00f4n To\u00e1n ho\u1eb7c V\u0103n ph\u1ea3i \u0111\u1ea1t \u2265 8,0. N\u1ebfu vi ph\u1ea1m b\u1ea5t k\u1ef3 \u0111i\u1ec1u ki\u1ec7n n\u00e0o, b\u1ea1n s\u1ebd b\u1ecb h\u1ea1 xu\u1ed1ng lo\u1ea1i Kh\u00e1 d\u00f9 \u0110TBhk cao.<\/p>\n

9.6. T\u00ednh ph\u1ea7n tr\u0103m ti\u1ebfn b\u1ed9 \u0111i\u1ec3m gi\u1eefa hai h\u1ecdc k\u1ef3 th\u1ebf n\u00e0o?<\/h3>\n

D\u00f9ng c\u00f4ng th\u1ee9c: % t\u0103ng = (\u0111i\u1ec3m k\u1ef3 sau \u2212 \u0111i\u1ec3m k\u1ef3 tr\u01b0\u1edbc) \/ \u0111i\u1ec3m k\u1ef3 tr\u01b0\u1edbc \u00d7 100. V\u00ed d\u1ee5 t\u1eeb 7,0 l\u00ean 7,7 l\u00e0 t\u0103ng (7,7\u22127,0)\/7,0 \u00d7 100 = 10%. \u0110\u00e2y l\u00e0 c\u00e1ch \u0111o ti\u1ebfn b\u1ed9 tr\u1ef1c quan v\u00e0 c\u00f4ng b\u1eb1ng h\u01a1n so v\u1edbi ch\u1ec9 nh\u00ecn ch\u00eanh l\u1ec7ch tuy\u1ec7t \u0111\u1ed1i.<\/p>\n

9.7. M\u00f4n n\u00e0o c\u00f3 h\u1ec7 s\u1ed1 m\u00f4n cao khi t\u00ednh \u0110TBhk?<\/h3>\n

T\u00f9y quy \u0111\u1ecbnh t\u1eebng th\u1eddi k\u1ef3 v\u00e0 t\u1eebng tr\u01b0\u1eddng. \u1ede nhi\u1ec1u c\u00e1ch t\u00ednh, To\u00e1n v\u00e0 Ng\u1eef v\u0103n c\u00f3 h\u1ec7 s\u1ed1 m\u00f4n 2 (n\u1eb7ng g\u1ea5p \u0111\u00f4i), c\u00e1c m\u00f4n c\u00f2n l\u1ea1i h\u1ec7 s\u1ed1 1. \u0110i\u1ec1u n\u00e0y ngh\u0129a l\u00e0 \u0111i\u1ec3m To\u00e1n, V\u0103n \u1ea3nh h\u01b0\u1edfng l\u1edbn t\u1edbi \u0110TBhk \u2014 n\u00ean \u01b0u ti\u00ean hai m\u00f4n n\u00e0y khi c\u1ea7n k\u00e9o \u0111i\u1ec3m t\u1ed5ng.<\/p>\n

10. K\u1ebft Lu\u1eadn<\/h2>\n

N\u1eafm v\u1eefng c\u00e1ch t\u00ednh ph\u1ea7n tr\u0103m \u0111i\u1ec3m trung b\u00ecnh<\/strong> h\u1ecdc k\u1ef3 kh\u00f4ng ch\u1ec9 gi\u00fap b\u1ea1n ki\u1ec3m tra h\u1ecdc b\u1ea1 ch\u00ednh x\u00e1c, m\u00e0 c\u00f2n l\u00e0 c\u00f4ng c\u1ee5 chi\u1ebfn l\u01b0\u1ee3c \u0111\u1ec3 l\u1eadp m\u1ee5c ti\u00eau v\u00e0 ph\u00e2n b\u1ed5 c\u00f4ng s\u1ee9c \u00f4n t\u1eadp h\u1ee3p l\u00fd. H\u00e3y nh\u1edb ba nguy\u00ean t\u1eafc c\u1ed1t l\u00f5i: \u0111i\u1ec3m trung b\u00ecnh m\u00f4n l\u00e0 trung b\u00ecnh c\u00f3 tr\u1ecdng s\u1ed1 (nh\u00e2n h\u1ec7 s\u1ed1 tr\u01b0\u1edbc khi c\u1ed9ng); m\u1ed7i c\u1ed9t \u0111i\u1ec3m chi\u1ebfm m\u1ed9t ph\u1ea7n tr\u0103m kh\u00e1c nhau t\u00f9y h\u1ec7 s\u1ed1; v\u00e0 x\u1ebfp lo\u1ea1i h\u1ecdc l\u1ef1c c\u1ea7n c\u1ea3 \u0110TBhk l\u1eabn \u0111i\u1ec3m s\u00e0n t\u1eebng m\u00f4n.<\/p>\n

Khi bi\u1ebft \u0111i\u1ec3m cu\u1ed1i k\u1ef3 chi\u1ebfm 30% (ho\u1eb7c 50%) \u0111i\u1ec3m trung b\u00ecnh m\u00f4n, b\u1ea1n s\u1ebd \u01b0u ti\u00ean \u0111\u00fang ch\u1ed7. Khi bi\u1ebft c\u00f4ng th\u1ee9c t\u00ednh ng\u01b0\u1ee3c \u0111i\u1ec3m c\u1ea7n \u0111\u1ea1t, b\u1ea1n s\u1ebd \u0111\u1eb7t m\u1ee5c ti\u00eau th\u1ef1c t\u1ebf thay v\u00ec m\u01a1 h\u1ed3. V\u00e0 khi l\u1eadp b\u1ea3ng theo d\u00f5i \u0111i\u1ec3m t\u1eeb \u0111\u1ea7u k\u1ef3, b\u1ea1n lu\u00f4n ch\u1ee7 \u0111\u1ed9ng thay v\u00ec b\u1ecb \u0111\u1ed9ng ch\u1edd k\u1ebft qu\u1ea3.<\/p>\n

\n\ud83c\udfaf T\u00ednh \u0111i\u1ec3m trung b\u00ecnh v\u00e0 ph\u1ea7n tr\u0103m tr\u1ecdng s\u1ed1 ngay!<\/strong><\/p>\n

\u0110\u1eebng t\u00ednh tay d\u1ec5 nh\u1ea7m. Truy c\u1eadp 1phantram.com<\/strong><\/a> \u0111\u1ec3 t\u00ednh ph\u1ea7n tr\u0103m \u0111i\u1ec3m trung b\u00ecnh, ph\u1ea7n tr\u0103m tr\u1ecdng s\u1ed1 t\u1eebng c\u1ed9t \u0111i\u1ec3m, ph\u1ea7n tr\u0103m t\u0103ng\/gi\u1ea3m gi\u1eefa c\u00e1c k\u1ef3 \u2014 mi\u1ec5n ph\u00ed, nhanh g\u1ecdn, ch\u00ednh x\u00e1c tr\u00ean m\u1ecdi thi\u1ebft b\u1ecb.\n<\/div>\n